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6y^2-41y+30=0
a = 6; b = -41; c = +30;
Δ = b2-4ac
Δ = -412-4·6·30
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-31}{2*6}=\frac{10}{12} =5/6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+31}{2*6}=\frac{72}{12} =6 $
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